leetcode-392. 判断子序列

题解思路

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class Solution {
public boolean isSubsequence(String s, String t) {
int n1 = s.length();
int n2 = t.length();

boolean[][] dp = new boolean[n1 + 1][n2 + 1];

for (int i = 1; i <= n1; i++) {
dp[i][0] = false;
}

for (int i = 0; i <= n2; i++) {
dp[0][i] = true;
}

for (int i = 1; i <= n1; i++) {
for (int j = 1; j <= n2; j++) {
if (dp[i][j-1]){
dp[i][j] = dp[i][j - 1];
}else {
if (s.charAt(i - 1) == t.charAt(j - 1) && dp[i-1][j-1]) {
dp[i][j] =dp[i - 1][j - 1];
}else {
dp[i][j] = dp[i][j - 1];
}
}
}
}

return dp[n1][n2];
}
}